Number Line Jumps HackerRank Solution

Number Line Jumps HackerRank Solution

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In this Number Line Jumps HackerRank solution, You are choreographing a circus show with various animals. For one act, you are given two kangaroos on a number line ready to jump in the positive direction (i.e, toward positive infinity).

  • The first kangaroo starts at location  and moves at a rate of  meters per jump.
  • The second kangaroo starts at location  and moves at a rate of  meters per jump.

You have to figure out a way to get both kangaroos at the same location at the same time as part of the show. If it is possible, return YES, otherwise return NO.

Example



After one jump, they are both at , (, ), so the answer is YES.

Function Description

Complete the function kangaroo in the editor below.

kangaroo has the following parameter(s):

  • int x1, int v1: starting position and jump distance for kangaroo 1
  • int x2, int v2: starting position and jump distance for kangaroo 2

Returns

  • string: either YES or NO

Input Format

A single line of four space-separated integers denoting the respective values of , , , and .

Constraints

Number Line Jumps HackerRank Solution

I will Provide solution in Multiple programming languages for you. If you are not able to find the code in required language then please share in comments so that our team can help you.

Problem Solution in Python

def kangaroo(x1, v1, x2, v2):
    for i in range(0,10000):
        d1= x1 + v1*i
        d2= x2 + v2*i
        if d1==d2:
            return 'YES'
            break
        else:
            continue
    return 'NO'

Problem Solution in JavaScript

function kangaroo(x1, v1, x2, v2) {
    // Write your code here
    if (x2 > x1 && v2 >= v1 || x2 < x1 && v2 <= v1) {
        return "NO";
    }


    let jumps = (x1 - x2) / (v2 - v1);


    if (jumps >= 0 && Number.isInteger(jumps)) {
        return "YES";
    } else {
        return "NO";
    }
}

Problem Solution in Java

public static String kangaroo(int x1, int v1, int x2, int v2) {
    // Write your code here
        String result = "NO";
        int kangaroo1 = x1+v1;
        int kangaroo2 = x2+v2;
       
        for(int i=0; i<10000; i++) {
            if(kangaroo1==kangaroo2) {
            result = "YES";
            break;
        }
            kangaroo1+=v1;
            kangaroo2+=v2;
        }


       
        return result;
    }

Problem Solution in C#

    public static string kangaroo(int x1, int v1, int x2, int v2)
    {
        string answer = "";        
        while(true){
            x1+=v1;
            x2+=v2;
            if(x1==x2){
                answer = "YES";
                break;
            }else if(x1>x2){
                answer = "NO";
                break;
            }
        }        
        return answer;
    }

Problem Solution in C++

string kangaroo(int x1, int v1, int x2, int v2) {
    if (v1 == v2) {
        return  x1 == x2 ? "YES" : "NO";
    }
    float steps = float(x2 - x1) / float (v1 - v2);
 
    if (steps >= 0 && std::floor(steps) == steps) {
        return "YES";
    }
    return "NO";
}

Problem Solution in Ruby

def kangaroo(x1, v1, x2, v2)
    # Write your code here
    while (x1 < x2 && v1 > v2)
        x1 +=v1
        x2 +=v2
        if x1 == x2
            return "YES"
        end
    end
    return "NO"
end
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