Grading Students HackerRank Problem Solution

Posted by admin August 1, 2023
Grading Students HackerRank Problem Solution
Grading Students HackerRank Problem Solution

In this HackerRank Sparse Arrays problem, we need to follow the hackerrank university grading policy and develop a program. HackerLand University has the following grading policy:

  • Every student receives a  in the inclusive range from  to .
  • Any  less than  is a failing grade.

Sam is a professor at the university and likes to round each student’s  according to these rules:

  • If the difference between the  and the next multiple of  is less than , round  up to the next multiple of .
  • If the value of  is less than , no rounding occurs as the result will still be a failing grade.

Examples

  •  round to  (85 – 84 is less than 3)
  •  do not round (result is less than 40)
  •  do not round (60 – 57 is 3 or higher)

Given the initial value of  for each of Sam’s  students, write code to automate the rounding process.

Function Description

Complete the function gradingStudents in the editor below.

gradingStudents has the following parameter(s):

  • int grades[n]: the grades before rounding

Returns

  • int[n]: the grades after rounding as appropriate

Input Format

The first line contains a single integer, , the number of students.
Each line  of the  subsequent lines contains a single integer, .

Constraints

Grading Students Hacker Rank Problem Solutions

I will Provide solution in Multiple programming languages for you. If you are not able to find the code in required language then please share in comments so that our team can help you.

Problem Solution in JavaScript

function gradingStudents(grades) {
    for(let i=0; i< grades.length; i++){
      if(grades[i] >= 38){
         if((grades[i] + 1) % 5 === 0){
          grades[i] = grades[i] +1;
          }else if((grades[i] + 2) % 5 === 0){
           grades[i] = grades[i] +2;
          }
      }
    }
  return grades;
}

Problem Solution in Python

def gradingStudents(grades):
    for i in range(len(grades)):
        if grades[i]<38:
            continue
        diff = 5 - grades[i] %5
        if diff<3:
            grades[i]+=diff


    return grades

Problem Solution in Java

List result = new ArrayList<>();
    for (Integer grade : grades) {
        int ost = grade % 5;
        int forRoundGrade = 5 - ost;


        if (grade < 38 || ost < 3) {
            result.add(grade);
        } else {
            result.add(grade + forRoundGrade);
        }
    }


    return result;

Problem Solution in C++

vector<int> gradingStudents(vector<int> grades) {
    for (unsigned short i = 0; i < grades.size(); ++i) {
        if (grades[i] < 38) continue;
        else {
            unsigned short grade = grades[i] % 5;
            if (grade > 2) grades[i] = grades[i] + (5 - grade);
        }
    }
    return grades;
}